[Rockhounds] Question?

[Axel Emmermann]

Hi Carolyn,

The general formula of gravity in relation to height is:

g(orbit) = g(surface) * (radius earth/(radius earth + height))²
In this case
G(at 1 mile) = g(surface) * (7926.28 miles/ (7926.28 miles + 1 mile))²
G(at 1 mile) = g(surface) * 0,99987890286002178793842460436531

So a cubic foot of glacial ice would weigh
0,99987890286002178793842460436531 times as much when weighed 1 mile above
the earth's surface as it would at ground level.

Still, I think that you wanted to know how much a column of 1 SQUARE foot
and 1 mile high would weigh... That would be in Earl's answer.

You can't say that I didn't answer the exact question, can you? LOL.

Cheers (and cheer up, I'm like that all the time and it drives my wife and
kids crazy)

Axel


> -----Oorspronkelijk bericht-----
> Van: rockhounds-bounces at lists.drizzle.com
[mailto:rockhounds-bounces at lists.drizzle.com]
> Namens Carolyn Reynard
> Verzonden: woensdag 14 januari 2009 15:33
> Aan: Rockhounds
> Onderwerp: [Rockhounds] Question?
> 
> To the list:
> 
> How does one find out  the weight of a cubic foot of glacial ice one mile
high?
> 
>  I have been searching glaciers but have not found the answer.
> 
> Carolyn Reynard
> 
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